Sqrt2f45E.cin

Sqrt2f45e.cin is the C++ routine to evaluate the infinitely growing superfunction of exponential, \(\mathrm{SuExp}_{\sqrt{2},5}\).

z_type f45E(z_type z){int n; z_type e,s;
DB coeu[21]={1.,
 0.44858743119526122890, .19037224679780675668,
 0.77829576536968278770e-1, 0.30935860305707997953e-1,
 0.12022125769065893274e-1, 0.45849888965617461424e-2,
 0.17207423310577291102e-2, 0.63681090387985537364e-3,
 0.23276960030302567773e-3, 0.84145511838119915857e-4,
 0.30115646493706434120e-4, 0.10680745813035087964e-4,
 0.37565713615564248453e-5, 0.13111367785052622794e-5,
 0.45437916254218158081e-6, 0.15642984632975371803e-6,
 0.53523276400816416929e-7, 0.18207786280204973113e-7,
 0.61604764947389226744e-8, 0.2e-8};
        e=exp(.32663425997828098238*(z-1.11520724513161));
        s=coeu[20]; for(n=19;n>=0;n--) { s*=e; s+=coeu[n]; }
        return 4.+s*e;}
 z_type F45E(z_type z){ DB b=sqrt(2.);
                        if(Re(z)<-1.) return f45E(z);
                        return exp(F45E(z-1.)*log(b));
                }