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  • File:Susinploat300.jpg
    ...o evaluate, approximately, the value of the nth iterate of f(x) ... If the formula is correct, it will take 3⋅1010 .. steps to reat 0.00001 from 1. .. ...x)\approx \sqrt{\frac{3}{n}}$, $x\approx 1$, $n$ lage ... How good is this formula? after 60000 iterations of the value 0.0071 and the discrepancy -4.7s-007 .
    (4,259 × 1,432 (460 KB)) - 08:53, 1 December 2018