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• Table of superfunctions
  : \( \!\!\!\!\!\!\!\!\!\!\!\! (2) ~ ~ ~ G(T(z))=G(z)+1 \) | \(\displaystyle \frac{-a^2}{z}\)
  11 KB (1,565 words) - 18:26, 30 July 2019
• Square root of exponential
  [[Square root of exponential]] \(\varphi=\sqrt{\exp}=\exp^{1/2}\) is half-iteration of the [[exponential]], id est, such function that its Function \(\sqrt{\exp}\) should not be confused with
  5 KB (750 words) - 18:25, 30 July 2019
• Iteration
  ...T.jpg|400px|thumb|Fig.1. Iterates of \(T(z)=z^2~\): \(~y\!=\!T^n(x)\!=\!x^{2^n}~\) for various \(n\)]] [[File:FacIteT.jpg|400px|thumb|Fig.2. Iterates of [[Factorial]]: \(~y\!=\!\mathrm{Factorial~}^{~n}(x)~\) for va
  14 KB (2,203 words) - 06:36, 20 July 2020
• Fourier-2 transform
  '''Fourier-2 transform''' is bidimensional [[Fourier transform]] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\! g(x,y)= \frac{1}{2\pi} \) \(\displaystyle\iint \mathrm dp ~\mathrm dq~ \exp(-i p x - i q y ) ~
  6 KB (954 words) - 18:27, 30 July 2019
• Квадратный корень из факториала
  [[File:SquareRootOfFactorial.png|400px|right|thumb| \(y\!=\! x!\) и \(y\!=\!\sqrt{!\,}(x)\) как функции от \(x\)]] ...из факториала ([[Square root of factorial]]), то есть \(\sqrt{\,!\,}\) - голоморфная функкция \(f\) такая, что
  6 KB (312 words) - 18:33, 30 July 2019
• Iterated integral
  (id est, \(\sqrt{-\!1}~\) ) in [[Mathematica]] and the [[Identity function]], which is also : \(\!\!\!\!\!\!\!\!\! (2)\displaystyle ~ ~ ~ J^m J^n = J^{m+n}\)
  9 KB (1,321 words) - 18:26, 30 July 2019
• Корень из факториала
  Символ \(\sqrt{\,!\,}\) установлен в качестве эмблемы Физфа
  7 KB (381 words) - 18:38, 30 July 2019
• Filog.cin
  z_type TaniaS(z_type z){int n; z_type s,t=z+z_type(2.,-M_PI);t*=2./9.; t=I*sqrt(t); if( fabs(Im(z))< M_PI && Re(z)<-2.51) return TaniaNega(z);
  2 KB (258 words) - 10:19, 20 July 2020
• Filog
  ...anchpoint \(z=1/\mathrm e\); the second goes through the point \(z\!=\!\pi/2\), where the fixed points of logarithm are \(\pm \mathrm i\). ...f the cut, the function has real values; in addition, at \(z=\ln\big(\sqrt{2}\big)\), these values are integer
  4 KB (572 words) - 20:10, 11 August 2020
• ArcCos
  :\( \displaystyle \arccos(z)=\frac{\pi}{2} - \arcsin(z)\) : \(\displaystyle \arccos[z]=\frac{\pi}{2}- \mathrm i ~ \mathrm{arccosh}(\mathrm i \, z)\)
  5 KB (754 words) - 18:47, 30 July 2019
• ArcCip
  : \(\displaystyle \mathrm{Cip}(z) = \frac{1}{z} -\frac{z}{2}+\frac{z^3}{24}+\frac{z^5}{720}+...~\), \(~ |z|\!\ll\! 1\) ...\mathrm{Cip}'(z)=0\) has several solutions. One of them is \(z=f_0\approx 2.798386045783887\) .
  8 KB (1,211 words) - 18:25, 30 July 2019
• Fac.cin
  1.01152306812684171, 1.51747364915328740, 2.26948897420495996, 3.00991738325939817, return s + log(2.*M_PI)/2. - z + (z+.5)*log(z);
  4 KB (487 words) - 07:00, 1 December 2018
• ArcSin
  : \(\displaystyle \sin(z) = \frac{\exp(\mathrm i z)- \exp(-\mathrm i z)}{2~ \mathrm i}\) \( \arcsin(z)= -\mathrm i \ln\Big( \mathrm i z + \sqrt{1-z^2} \big)\)
  9 KB (982 words) - 18:48, 30 July 2019
• ArcCosc
  : \(\mathrm{Sazae} \approx ~ 2.798386045783887\) \frac{2(z\!-\!\mathrm{Tarao})}
  8 KB (1,137 words) - 18:27, 30 July 2019
• Acosc.cin
  z_type acoscL(z_type z){ int n; z_type s,q; z*=-I; q=I*sqrt(1.50887956153832-z); z_type acoscB(z_type z){ z_type t=0.33650841691839534+z, u=sqrt(t), s; int n;
  1 KB (219 words) - 18:46, 30 July 2019
• Acosc1.cin
  if(Im(z)<0){if(Re(z)>=0){return I*log( z + sqrt(z*z-1.) );} else{return I*log( z - sqrt(z*z-1.) );}}
  3 KB (436 words) - 18:47, 30 July 2019
• Acosc1
  ..._1 - \sqrt{ \frac{2}{\mathrm{Tarao}_1 } (\mathrm{Tarao}_1\!-\!x) } + \frac{2\, (\mathrm{Tarao}_1 \!-\! x )}{3~ \mathrm{Sazae}_1~ \mathrm{Tarao}_1}\) \sqrt{
  6 KB (896 words) - 18:26, 30 July 2019
• ArcFactorial
  : \(\mathrm{ArcFactorial}(2)=2\) ...aystyle \mathrm{ArcFactorial}\left( \frac{\sqrt{\pi}}{2}\right)\!=\frac{1}{2}\)
  3 KB (376 words) - 18:26, 30 July 2019
• Bessel transform
  \(\mathrm{HankelKernel}(p,x)= \frac{1}{2 pi} \mathrm{BesselJ}_\nu(2 \pi px)\) \(\mathrm{BesselKernel}(p,x)= \mathrm{BesselJ}_\nu(2 \pi px)\)
  8 KB (1,183 words) - 10:21, 20 July 2020
• Absorbing Schroedinger
  ...\!\!\!\! (2) ~ ~ ~ \mathrm i ~ \hbar ~ \dot \Psi = \frac{-\hbar^2 \nabla^2}{2m} \Psi + U(\vec x) ~ \Psi -\mathrm i ~ V(\vec x) ~ \Psi \) : \(\displaystyle \!\!\!\!\!\!\!\!\!\! (7) ~ ~ ~ \omega - (c+\mathrm i s)^2 = -\mathrm i \gamma\)
  15 KB (2,070 words) - 18:47, 30 July 2019

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