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  • Numerator in the formula above is transformed as follows: Derivation of Niklas Carlsson;s formula. Cited by the state for December 2013:
    13 KB (2,088 words) - 06:43, 20 July 2020
  • File:Susinploat300.jpg
    ...o evaluate, approximately, the value of the nth iterate of f(x) ... If the formula is correct, it will take 3⋅1010 .. steps to reat 0.00001 from 1. .. ...x)\approx \sqrt{\frac{3}{n}}$, $x\approx 1$, $n$ lage ... How good is this formula? after 60000 iterations of the value 0.0071 and the discrepancy -4.7s-007 .
    (4,259 × 1,432 (460 KB)) - 08:53, 1 December 2018
  • ...0.00001 from 1. .. fn(x)≈3n‾‾√, x≈1, n lage ... How good is this formula? after 60000 iterations of the value 0.0071 and the discrepancy -4.7s-007 . ...n line. Kursernas Hemsidor denotes this approximation [[Niklas Carlsson's formula]].
    15 KB (2,314 words) - 18:48, 30 July 2019