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- ...to evaluate the infinitely growing superfunction of exponential, \(\mathrm{SuExp}_{\sqrt{2},5}\).1 KB (108 words) - 18:47, 30 July 2019
- ...с.11.4 || \(y\!=\!\mathrm{tet}_\eta(x)\!=\!F_{3}(x)\) || \(y\!=\!\mathrm{SuExp}_{\eta,3}(x)\!=\!F_{3}(x)\). | стр.138, рис.11.4 || \(y\!=\!\mathrm{SuExp}_{\eta,3}(x)\!=\!F_{1}(x)\) || \(y\!=\!\mathrm{tet}_\eta(x)\!=\!F_{1}(x)\).19 KB (1,132 words) - 20:36, 16 July 2023