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• Корень из факториала
  : \(h(h(z))=z\) для некоторого домена значений \(z\).
  7 KB (381 words) - 18:38, 30 July 2019
• Уравнение Шредера
  : \( \!\!\!(1) ~ ~ ~ T(f(z))=f(kz)\) : \(\!\!\!(2) ~ ~ ~ T(F(z))=F(z+1)\)
  5 KB (116 words) - 18:37, 30 July 2019
• Коррупция
  Евгения Альбац. Кто вы, доктор Z? № 5 (274) от 18 февраля 2013 года.</ref>. Он состои ...ч активистов за компьютерами». Блогер doct-z — о создании глобального проекта по поис
  219 KB (3,034 words) - 19:23, 7 November 2021
• Filog.cin
  ...\(\exp(z)\) is evaluated with routine complex double Filog(complex double z) below z_type ArcTania(z_type z) {return z + log(z) - 1. ;}
  2 KB (258 words) - 10:19, 20 July 2020
• Filog
  \(f=\mathrm{Filog}(z)\) is solution of the equation for base \(b\!=\!\exp(z)\).
  4 KB (572 words) - 20:10, 11 August 2020
• Tetration to Sheldon base
  ...\!\!\! (1) \displaystyle ~ ~ ~ \exp(a~ \mathrm{tet_s}(z)) = \mathrm{tet}_s(z\!+\!1)\) ...ex half-line, except some facility of the negative part of the real axis \(z<-2\); the tetration should have the cutline there.
  5 KB (707 words) - 21:33, 13 July 2020
• GLxw2048.inc
  ...-5718-09-02188-7/home.html D.Kouznetsov. (2009). Solutions of F(z+1)=exp(F(z)) in the complex plane.. Mathematics of Computation, 78: 1647-1670.</ref>. { int m,j,i; long double z1,z,xm,xl,pp,p3,p2,p1;
  108 KB (1,626 words) - 18:46, 30 July 2019
• Iterated Cauchi
  T(F(z))=F(z+1) It is assumed that \(F(z)\) is holomorphic at least in the strip \(\Re(z)\le 1\), and
  6 KB (987 words) - 10:20, 20 July 2020
• Institute for Laser Science
  | doi=10.1007/s00340-005-2083-z http://maps.google.com/maps?q=34.85,138.55&ie=UTF8&om=1&z=19&ll=35.657952,139.54128&spn=0.001077,0.002942&t=h
  12 KB (1,757 words) - 07:01, 1 December 2018
• Fsexp.cin
  // complex<double>FSEXP( complex <double> z) z_type fima(z_type z){ z_type c,e;
  9 KB (654 words) - 07:00, 1 December 2018
• Факториал
  : \( F(z)=z\cdot F(z\!-\!1)\) : \(\mathrm{Factorial}(z)=z!\)
  2 KB (59 words) - 18:33, 30 July 2019
• ArcCos
  : \( \cos(\arccos(z))=z\) ...phic in the whole complex plane except the halflines \(z\!\le\! -1\) and \(z\!\ge\! 1\).
  5 KB (754 words) - 18:47, 30 July 2019
• ArcCip
  : \(\displaystyle \mathrm {Cip}(z)=\frac{\cos(z)}{z}\) <!-- Complex map of function Cip is shown at right.!--> : \(\displaystyle \mathrm{Cip}(\mathrm{ArcCip}(z))=z\).
  8 KB (1,211 words) - 18:25, 30 July 2019
• SuperFactorial.cin
  z_type superfac0(z_type z){ int n; z_type s; z_type e=exp(k*z);
  1 KB (88 words) - 14:55, 20 June 2013
• Fac.cin
  z_type fracti(z_type z){ z_type s; int n; DB a[17]= s=a[16]/(z+19./(z+25./(z))); for(n=15;n>=0;n--) s=a[n]/(z+s);
  4 KB (487 words) - 07:00, 1 December 2018
• ArcSin
  : \(\displaystyle \sin(z) = \frac{\exp(\mathrm i z)- \exp(-\mathrm i z)}{2~ \mathrm i}\) \(f=\arcsin(z)\) is holomorphic solution \(f\) of equation
  9 KB (982 words) - 18:48, 30 July 2019
• Coshc
  : \(\displaystyle \mathrm{coshc}(z)=\frac{\cosh(z)}{z}\) : \(\displaystyle \cosh(z)=\cos(\mathrm i z) = \frac{\mathrm e^z+\mathrm e^{-z} }{2}\)
  4 KB (509 words) - 18:26, 30 July 2019
• ArcCosc
  : \( \displaystyle \mathrm{cosc}(z)=\frac{\cos(z)}{z}\) : \(\displaystyle \mathrm{sinc}(z)=\frac{\sin(z)}{z}\)
  8 KB (1,137 words) - 18:27, 30 July 2019
• Cosc
  : \( \displaystyle \mathrm{cosc}(z)=\frac{\cos(z)}{z}\) : \( \displaystyle \mathrm{sinc}(z) = \frac{ \sin(z)}{z}\)
  4 KB (649 words) - 18:26, 30 July 2019
• Wakame
  : \(\!\!\!\!\!\!\!\!\! (4) ~ ~ ~ ~ \mathrm{cohc}(z)=\frac{\cosh(z)}{z}\); ...\!\!\!\! (5) ~ ~ ~ ~ \mathrm{cohc}'(z)=\frac{\sinh(z)}{z}-\frac{\cosh(z)}{z^2}\)
  4 KB (581 words) - 18:25, 30 July 2019

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